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4 Answers

1 votes
1 votes

TCP uses 32 bit sequence number.

To wrap around completely we must send 2 32 bytes (ie 2 35 bits)

Time taken to send 10 giga bits (10 x 2 30  bits) = 1 sec

Time taken to send 2 35 bits = 2 35 /10*2 30 =3.2 sec

answer D

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0 votes

Option -B is right.

Bw=10*2^30

Time required to send one byte=1/10*2^30

So for 2^32 byte(sequence number is 32 bit)=2^32/2^30*10=0.4sec

Image result for tcp header format

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Ans-b

1 Gbps = 10^9  ( B.W)

10 Gbps = 10^10 

now move to question-

10Gbps means in 10^10 seq. no.  can be assign in    1 sec 

           so             1 seq no     take    (1/10^10 )   sec

so   2^32   seq  no take 2^32/10^10   sec = 0.429  sec  = 0.4 sec(approx) 

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go_editor asked Sep 28, 2016
533 views
What layer of the OSI model is designed to perform error recovery functions?physicaldata linknetworktransport