2 votes 2 votes Computer Networks computer-networks tcp + – Payal Rastogi asked Jul 25, 2016 Payal Rastogi 654 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes TCP uses 32 bit sequence number. To wrap around completely we must send 2 32 bytes (ie 2 35 bits) Time taken to send 10 giga bits (10 x 2 30 bits) = 1 sec Time taken to send 2 35 bits = 2 35 /10*2 30 =3.2 sec answer D sh!va answered Jul 25, 2016 sh!va comment Share Follow See all 2 Comments See all 2 2 Comments reply monty commented Sep 16, 2016 reply Follow Share my answer is 3.435 because bandwidth in terms power of 10. 1 votes 1 votes Sushant Gokhale commented Oct 2, 2016 reply Follow Share @SHiva. WHy are you just calculating the TCP payload transmission? Isnt the header also transmitted? Lets consider min frame size = 20B header + 1B TCP payload = 21B Time required for 21B transmission = $\frac{21*8}{10^{9}}$ Niw, 1 sequnce num $\equiv$ $\frac{21*8}{10^{9}}$ sec $2^{32}$ seq numbers $\equiv$ ? = 21*32 = 672 sec 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Option -B is right. Bw=10*2^30 Time required to send one byte=1/10*2^30 So for 2^32 byte(sequence number is 32 bit)=2^32/2^30*10=0.4sec Paras Nath answered Sep 16, 2016 Paras Nath comment Share Follow See 1 comment See all 1 1 comment reply Pavan Kumar Munnam commented Sep 16, 2016 reply Follow Share Bandwidth is Giga bits per sec not Giga bytes per sec 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes option d is appropiate one vijju answered Sep 27, 2016 vijju comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Ans-b 1 Gbps = 10^9 ( B.W) 10 Gbps = 10^10 now move to question- 10Gbps means in 10^10 seq. no. can be assign in 1 sec so 1 seq no take (1/10^10 ) sec so 2^32 seq no take 2^32/10^10 sec = 0.429 sec = 0.4 sec(approx) Shailendra_ answered Nov 28, 2019 Shailendra_ comment Share Follow See all 0 reply Please log in or register to add a comment.