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As given polynomial is x3+1 =>1001

with this directly we can say option D because we add 3 digits more for the data and this satisfied only by option D

But general solution could be

1001) 11001001000(1100011
       1001
     ----------------
       01011
        1001
     ----------------
        00100
         0000
     ----------------
         01000
          1001
     ----------------
          0001100
             1001
     ----------------
             01010
              1001
     ----------------
              0011

so the message transmitted is 11001001011

Option D

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