As given polynomial is x3+1 =>1001
with this directly we can say option D because we add 3 digits more for the data and this satisfied only by option D
But general solution could be
1001) 11001001000(1100011
1001
----------------
01011
1001
----------------
00100
0000
----------------
01000
1001
----------------
0001100
1001
----------------
01010
1001
----------------
0011
so the message transmitted is 11001001011
Option D