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If number on the black die divides the number on red die, respective numbers on the black die and red die must be any of the following

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6), (2,2),(2,4),(2,6), (3,3),(3,6), (4,4), (5,5), (6,6)

Total number of possible outcomes = 14

The probability that the number of the black die divides the

number of red die = $\frac{14}{36}$

Hence,Option(c)$\frac{14}{36}$.

1 vote

1st die (1,2,3,4,5,6): 6 ways

2nd die (1,2,3,4,5,6): 6 ways

Thus On tossing two dice, total number of possible outcomes = 6 x 6 = 36

- If 1 comes in black dice, number on red dice divisible by 1 = {1,2,3,4,5,6} // 6 success
- If 2 comes in black dice, number on red dice divisible by 2 = {2,4,6} // 3 success
- If 3 comes in black dice, number on red dice divisible by 3 = {3,6} // 2 success
- If 4 comes in black dice, number on red dice divisible by 2 = {4} // 1 success
- If 5 comes in black dice, number on red dice divisible by 2 = {5} // 1 success
- If 6 comes in black dice, number on red dice divisible by 2 = {6} // 1 success

Total number of favorable outcomes = 14

Required probability = 14/36