If number on the black die divides the number on red die, respective numbers on the black die and red die must be any of the following
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6), (2,2),(2,4),(2,6), (3,3),(3,6), (4,4), (5,5), (6,6)
Total number of possible outcomes = 14
The probability that the number of the black die divides the
number of red die = $\frac{14}{36}$
Hence,Option(c)$\frac{14}{36}$.