The Gateway to Computer Science Excellence
+1 vote
556 views

Consider a proposition given as:

"$x \geq 6$, if $x^2 \geq$ 25 and and its proof as:

If x $\geq$ 6, then $x^2 =x.x \geq 6.6 = 36 \geq 25$

Which of the following is correct with respect to the given proposition and its proof?

  1. The proof shows the converse
  2. The proof starts by assuming what is to be shown
  3. The proof is correct and there is nothing wrong
    1. ​a only
    2. c only
    3. a and b
    4. b only
in Mathematical Logic by Veteran (105k points)
recategorized by | 556 views

1 Answer

+1 vote

let p:  x>=6  q: x^2=25 then given statement can be written as q->p

and its given proof may be written as p->q which is converse of q->p so  

a)  is correct

we have to prove p and we are assuming it in our proof so b is also true 

so ans is C) a and b  

note := the proof is not correct it is not following any standards of logic

by Boss (49.3k points)
Answer:

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,737 questions
57,365 answers
198,494 comments
105,262 users