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The casual form of the disjunctive normal form $\neg A \vee \neg B \vee \neg C \vee D$ is:

  1. $A \wedge B \wedge C \Rightarrow D$
  2. $A \vee B \vee C \vee D \Rightarrow true$
  3. $A \wedge B \wedge C \wedge D \Rightarrow true$
  4. $A \wedge B \wedge C \wedge D \Rightarrow false$
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2 Answers

Best answer
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8 votes

It should be clausal form rather than casual 

as we know A->B is equivalent to ~AVB  now checking option A

ABCD  applying above equivalence 

~(ABC)V D           applying de-morgans law

=>~A V ~B V ~C V D which is given in the question hence ans is A 

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