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Suppose a digitazed voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it is assumed that each sample required 8 bits?

  1. 32 kbps
  2. 64 kbps
  3. 128 kbps
  4. 256 kbps
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Bandwidth of analog channel is 8K/Sec.
Required sample 2samples /hz. =2s.
one sample is 8 bit.
so bit rate = (8k)*2*(8 bit)=128 kbps.

Answer:

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