Why option a is correct pls explain

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Bikram
asked
in Set Theory & Algebra
Aug 6, 2016

312 views
1 vote

A relation $R$ is defined as $xRy$ , if $x$ and $y$ are NOT equal. This relation $R$ is

- symmetric but not reflexive
- symmetric and transitive but not reflexive
- an equivalent relation
- none of reflexive or symmetric or transitive

@kavita_joshi

xRy and yRx then xRx so it is not transitive .

read this slide --> http://www3.cs.stonybrook.edu/~pfodor/courses/CSE215/L14-Relations.pdf

1

3 votes

**relation hold iff x!=y**

**1 :for reflexive: xRx (x!=x) false ;**

**2: for symmetric xRy=yRx ( x!=y and y!=x ) true**

**3: for transitive lets : (x,y)=(1,2) (y,z) =(21) (x,z)=(11)**

**here xRy ,yRz hold but xRx doesn't (as 1=1 )**

@satendra That is incorrect.

$A=\left \{1,2,3 \right \}$

Relation R on A = $A=\left \{(1,2) ,(2,1), (1,1) \right \}$

Transitive but not reflexive.

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