2 votes 2 votes Using p=3, q=13, d=7 and e=3 in the RSA algorithm, what is the value of ciphertext for a plain text 5? 13 21 26 33 Computer Networks ugcnetcse-dec2015-paper2 computer-networks network-security + – go_editor asked Aug 8, 2016 • recategorized Nov 9, 2017 by Devshree Dubey go_editor 2.8k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes all options are incorrect and perhaps question too everything (e,d,p,q,P) is given in question just need to verfiy from the ans but options are not verificable C=P^e mod n P=5 , e=3 ,n=pq=39 C=5^3mod39=>125mod39=8 not in option Sanjay Sharma answered Aug 8, 2016 Sanjay Sharma comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Encryption: C=T^e (mod pq) =5^3(mod39) =26mod39 =26 sh!va answered Aug 8, 2016 sh!va comment Share Follow See 1 comment See all 1 1 comment reply Nishahooda_27 commented Nov 29, 2019 reply Follow Share How 5*3 gives you 26?.. its 125mod39 so ans is 8 .no option is correct 0 votes 0 votes Please log in or register to add a comment.
