Any one explain this one please..

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let we have seven men as a,b,c,d,e,f,g

we have to pick 2 men to form a pair

no. of ways to pick 2 men from 7 = C(7,2)

=21 pairs

after picking 2 men from 7 people we are left with 5 men's , again we need one more pair to play

so it can be done in C(5,2) = 10 ways

total = 21*10

=210

now if ab is picked and played against cd similarly cd is picked and plays against ab

order does not matter for each pair

so total games played = 210/2

=105

we have to pick 2 men to form a pair

no. of ways to pick 2 men from 7 = C(7,2)

=21 pairs

after picking 2 men from 7 people we are left with 5 men's , again we need one more pair to play

so it can be done in C(5,2) = 10 ways

total = 21*10

=210

now if ab is picked and played against cd similarly cd is picked and plays against ab

order does not matter for each pair

so total games played = 210/2

=105