The minimum number of cards to be dealt from an arbitrarily shuffled deck of 52 cards to guarantee that three cards are from same suit is
There are 4 sets of cards. So, up till 8 cards there is a chance that no more than 2 cards are from a given set. But, once we pick the 9th one, it should make 3 cards from any one of the sets. So, (C) is the answer.
Can this question be solved by calculating expectation:
Expectation of getting three cards from same deck->
E(x) = 13*(13/52) + 12*(12/51) + 11*(11/50)
= 8.49 => 9 cards
Hence 9 is the answer.
Is it correct?
Let's say |c| = 5 and |p| = ...
The fact is to improve the maximum ...