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Two cards are drawn together from a pack of 52 cards, What is the probability that One is spade and other is king??

total prob =1/52+1/52 =1/26 ans

### 1 comment

what if both are same,ie,in only one attempt we get spade king and spade card too?
Total sample space = 52C2

No. of king = 4

so probability = (13 * 4 ) / 52C2
With Replacement:

$\frac{_{1}^{13}\textrm{C} *_{1}^{4}\textrm{C} }{_{1}^{52}\textrm{C} *_{1}^{52}\textrm{C} }$

Without Replacement:

$\frac{(_{1}^{1}\textrm{C} *_{1}^{3}\textrm{C})+(_{1}^{12}\textrm{C}*_{1}^{4}\textrm{C})) }{_{2}^{52}\textrm{C} }$
by

@udditpto , I think ans should be p= 1/26  ...
yes and that case without replacement will be the answer @vijay
edited by

Yes @Srestha... :)

And With replacement -

$\frac{2*(12C2 * 4C1 + 1C1 * 3C1) +1}{52C1*52C1}$

where,

2* 12C2 * 4C1   - >  In first throw its a spade but not king and in 2nd throw its a king and vice versa.
2 *1C1 *3C1      - >  In first throw its a king without spade and in 2nd throw its a king with spade..and vice-versa.
1  - >  In first throw its a king with spade and in 2nd throw its same card as first one.

1 vote