UGC NET CSE | December 2011 | Part 2 | Question: 33

Question

If an integer needs two bytes of storage, then the maximum value of unsigned integer is

• A. $2^{16} – 1$
• B. $2^{15} – 1$
• C. $2^{16}$ 
• D. $2^{15}$

Answer 1

A. 2¹⁶-1.

2 bytes=16 bits therefore 2^16 possible values 
But since values start from 0,there's one less value for positive numbers. So -1

Answer 2

Ans: A 2 bytes= 16 bits

so, 0 to (2^16)-1