2 votes 2 votes If an integer needs two bytes of storage, then the maximum value of unsigned integer is $2^{16} – 1$ $2^{15} – 1$ $2^{16}$ $2^{15}$ Programming and DS ugcnetcse-dec2011-paper2 programming-in-c data-types + – makhdoom ghaya asked Aug 19, 2016 • recategorized Oct 10, 2018 by Pooja Khatri makhdoom ghaya 1.6k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 1 votes 1 votes A. 216-1. 2 bytes=16 bits therefore 2^16 possible values But since values start from 0,there's one less value for positive numbers. So -1 Prajwal Bhat answered Aug 20, 2016 • selected Aug 20, 2016 by Arjun Prajwal Bhat comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Ans: A 2 bytes= 16 bits so, 0 to (2^16)-1 rishu_darkshadow answered Sep 14, 2017 rishu_darkshadow comment Share Follow See all 0 reply Please log in or register to add a comment.