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Let us consider that the original point is (x,y) and new transformed point is (x’,y’). Further Sh$_x$ and Sh$_y$ are shearing factors in x and y directions. If we perform the y direction shear relative to x=s$_{ref}$ then the transformed point is given by

  1. $x’=x+Sh_x.(y-y_{ref}); y’=y$
  2. $x’=x; y’=y.Sh_x$
  3. $x’=x; y’=Sh_y(x-x_{ref})+y$
  4. $x’=Sh_y.y; y’=y.(x-x_{ref})$
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Ans is (C)

if we perform x direction shear with reference to y axis, then

x′= x + Shx.(y−yref);     y′=y

if we perform y direction shear with reference to x axis, then

x′ = x;    y′ = Shy(x−xref) + y
Answer:

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