1 votes 1 votes Let us consider that the original point is (x,y) and new transformed point is (x’,y’). Further Sh$_x$ and Sh$_y$ are shearing factors in x and y directions. If we perform the y direction shear relative to x=s$_{ref}$ then the transformed point is given by $x’=x+Sh_x.(y-y_{ref}); y’=y$ $x’=x; y’=y.Sh_x$ $x’=x; y’=Sh_y(x-x_{ref})+y$ $x’=Sh_y.y; y’=y.(x-x_{ref})$ Computer Graphics ugcnetcse-june2016-paper3 computer-graphics + – go_editor asked Aug 20, 2016 • recategorized Nov 7, 2017 by Devshree Dubey go_editor 4.8k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes Ans is (C) if we perform x direction shear with reference to y axis, then x′= x + Shx.(y−yref); y′=y if we perform y direction shear with reference to x axis, then x′ = x; y′ = Shy(x−xref) + y Mayank Malik answered Sep 6, 2018 Mayank Malik comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes X'=x and y'=shy(x-xref)+y option c is correct Nbhardwaj answered Sep 11, 2019 Nbhardwaj comment Share Follow See all 0 reply Please log in or register to add a comment.