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UGC NET CSE | June 2016 | Part 3 | Question: 29

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Assume that we need to download text documents at the rate of 100 pages per minute. A page is in average of 24 lines with 80 characters in each line requires 8 bits. Then the required bit rate of the channel is

  1. 1.636 Kbps
  2. 1.636 Mbps
  3. 3.272 Mbps
  4. 3.272 Kbps
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2 Answers

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9 votes

All options are incorrect

Equation will be: 

100 * 24 * 80 * 8 = 1536000 (Don't know why people say it is 1636000)

1536000 bits will be downloaded in 1 minutes i.e. 60 seconds and in one second it would be:

1536000 / 60 = 25600 bits

So answer should be 25.6 Kbps

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100*24*80*8 = 1636000bps = 1.636Mbps
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