Hi sir,

your answer is correct but small correction for 1st row 2nd column dij=+25

d12=c12-(u1+v2)

=30-(-195+200)=25

your answer is correct but small correction for 1st row 2nd column dij=+25

d12=c12-(u1+v2)

=30-(-195+200)=25

1 vote

The following transportation problem

A | B | C | Supply | |

I | 50 | 30 | 220 | 1 |

II | 90 | 45 | 170 | 3 |

III | 250 | 200 | 50 | 4 |

Demand | 4 | 2 | 2 | 0 |

$\begin{array}{|l|l|l|l|l|} \hline & \text{A} & \text{B} & \text{C} & \text{Supply} \\\hline \text{I} & \text{50} & \text{30} & \text{220} & \text{1} \\\hline \text{II} & \text{90} & \text{45} & \text{170} & \text{3} \\\hline \text{III} & \text{250} & \text{200} & \text{50} & \text{4} \\\hline \text{Demand} & \text{4} & \text{2} & \text{2} & \text{0} \\\hline \end{array}$

Has a solution

A | B | C | |

I | 1 | ||

II | 3 | 0 | |

III | 2 | 2 |

$\begin{array}{|l|l|l|}\hline \text{} & \text{A} & \text{B} & \text{C} \\\hline \text{I} & \text{1} & \text{} & \text{} \\\hline\text{II} & \text{3} & \text{0} & \text{} \\\hline\text{III} & \text{} & \text{2} & \text{2} \\\hline\end{array}$

The above solution of a given transportation problem is

- Infeasible solution
- optimum solution
- non-optimum solution
- unbounded solution

2 votes

1

Hi sir,

your answer is correct but small correction for 1st row 2nd column dij=+25

d12=c12-(u1+v2)

=30-(-195+200)=25

your answer is correct but small correction for 1st row 2nd column dij=+25

d12=c12-(u1+v2)

=30-(-195+200)=25

0

The number of allocations are 4 only (0 allocation is by default for every cell), so shouldn't it be (A) Infeasible?