## 5 Answers

**Answer is ****D.**

See we can simplify each equation given in the option and get that all of them gives $xy +wy$. But let think in another way.

$1^{st}$ option is written in $POS$ form, as we can check we get the same if we consider the following implicants.

which is $(w+x)y$

for the second one

Which gives $wy+xy$

now for 3rd one, we can verify like this

which is $(w+x)(\bar w+y)(\bar x+y)$

So as we can verify each equation in a given K-Map, **so the answer is option D**

### 9 Comments

**Answer is ****D.**See we can simplify each equation given in the option and get that all of them gives xy +wy. But let think in other way.

1st option is written in POS form, as we can check we get the same if we consider the following impicants.

which is (w+x)y

for second one

Which gives wy+xy

now for 3rd one we can verify like this

which is (w+x)(ˉw+y)(ˉx+y)

So as we can verify each equation in a given KMap, **so answer is D**