The following arrangement of master-slave flip flops
has the initial state of P, Q as 0, 1 (respectively). After a clock cycle the output state P, Q is (respectively),
Yes, you are right that in asynchronous counter the output of 1FF is given to other FF but the output is given as the Clock of other FF while in the synchronous we have same clock.
Please Correct me if I am wrong.
@ankitrokdeonsns you were right in some website and books it is written in question "after three clock cycles"
IF the question were to calculate the output after 3 clock cycles . Would the answer be 1,1...?
IS my approach correct ?
now when clock is aplied J= 1 and K=1 then (it do complement of P) i.,e output at p = 1 and at same time FF D has input 0 so it change Output Q as ) only [ on D-FF input = output]
SO output will be p= 1 and Q= 0
[ keep in mind both FF work at same time dont wait for 1st complete then second will start].
@sittian hopw you got it now.
-> As there is Master Slave configuration, 1st flipflop will respond to the positive edges and the 2nd flipflop to the negative edges.
-> As the given Flipflops are synchronous,(clock is simultaneously given to both FFs) $Q$ responds according to immediate values of $P$.
-> Thus, after 3 cycles, as shown in the diagram, $P = 1$ and $Q=0$