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Answer should  be a) coz if in 60 min 20 req are made then in 45 minute 15 req are made.

By Poisson distribution $P (k) = \frac{ G^k \times e^{-G}}{k!}.$

Here value of $k$ is number of requests made in given time which is 0. $G$ is avg requests  per 45 min. Substituting in formula and get $e^{-15}$  as result.
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2 votes
Answer should be : A

Poisson distribution p(k)= (G^k*e^-G)/k!

here k is no. of request in given time =0  bcz there is no request in 45 minutes

G is avg. request per 45 minutes = (45/60)*20=15

put eact value in formula: (15^0*e^-15)/0!

=e^-15
Answer:

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