In a paged memory, the page hit ratio is 0.35. The time required to access a page in secondary memory is 100 ns. The time required to access a page in primary memory is 10 ns. The average time required to access a page is
@Sahin This is not blind hit and trial. First hierarchical access is assumed. Then, simultaneous access is assumed.
Time required to access a page in memory = Look in page table + look in memory
Had it been given that time to access main memory =10ns then we would have done 0.35(10+10) and for page miss part we have to try out all options. First by treating it like .65(100+10) then if options don’t match then considering 100ns as page fault service time we take .65(100)
So answer should be either 75 or 68.5 as described in best answer.