In a paged memory, the page hit ratio is 0.35. The time required to access a page in secondary memory is 100 ns. The time required to access a page in primary memory is 10 ns. The average time required to access a page is
@MiNiPanda
@Sahin This is not blind hit and trial. First hierarchical access is assumed. Then, simultaneous access is assumed.
Unless told in question no need to consider address translation time. Here
time required to access a page in primary memory
means it includes address translation time.
Time required to access a page in memory = Look in page table + look in memory
Had it been given that time to access main memory =10ns then we would have done 0.35(10+10) and for page miss part we have to try out all options. First by treating it like .65(100+10) then if options donβt match then considering 100ns as page fault service time we take .65(100)
So answer should be either 75 or 68.5 as described in best answer.