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consider two 4-bit numbers A=A3 A2 A1 A0 and B=B3 B2 B1 B0 and the expression x=AiBi+AiBi for  i=0,1,2,3. the expression A3B3+x3A2B2+x3x2A1B1+x3x2x1A0B0 evaluates to 1 if

a- A=b

b-A!=b

c-A>B

d-A<B

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Ans is c as after putting xi values in expression if uh look closely if a>b then ab bar will hold 1observe closely

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