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What will be the output of the program?
#include<stdio.h>

int main()
{
    char c=48;
    int i, mask=01;
    for(i=1; i<=5; i++)
    {
        printf("%c", c|mask);
        mask = mask<<1;
    }
    return 0;
}
    A.    12400
    B.    12480
    C.    12500
    D.    12556
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2 Answers

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When %c is given in printf, the character corresponding to the 8 bit value being passed is printed. Unless otherwise stated, we can assume ASCII characters being used.

char c=48 takes the ASCII value of 48 which is '0';

c=48 binary number 00110000

mask 00000001

c|mask(unary OR operator, use binary value and then OR operation)=00110000+00000001=00110001=49

Now 49 is equal to ASCII value 1, 50 is ASCII value 2 etc.

So, it will print 12480
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