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3 votes
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The logic expression for the output of the circuit shown in the figure is

  1. $\bar{A} \bar{C}+ \bar{B}\bar{C}+CD$
  2. $A\bar{C}+B\bar{C}+\bar{C}D$
  3. $ABC + \bar{C}\bar{D}$
  4. $\bar{A}\bar{B}+\bar{B}\bar{C}+\bar{C}\bar{D}$
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3 Answers

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The logical expression can be written as:

$\left[\overline{(A+B)}+C\right].\left[(C+D)\right]$

Applying De-morgans' law:

$\left[(\bar A.\bar B)+C\right].(C+D)$

$\bar A\bar B C+\bar A\bar BD+C+CD$

taking $C$ as common here;

$C(\bar A\bar B+1+D)+\bar A\bar BD$

$\because (1+x=1)$

$\therefore \bar A\bar BD+C$

Note: none of the options are correct here.

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