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Find the minimum sum of products form of the below Logic function :

$$F(A,B,C,D) = \sum m(0,2,8,10,15) + \sum d(3,11,12,14)$$

where $m$ and $d$ are min-terms and don’t care conditions respectively.

  1. $AC +\bar BC \bar D +B\bar C $
  2. $\bar B  \bar D  + AC$
  3. $\bar AC +BC+\bar B\bar C \bar D$
  4. $B\bar C\bar D + \bar BA + CA$
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  00 01 11 10
00 1   X 1
01        
11 X   1 X
10 1   X 1

We get 2 prime implicants,

$\bar B \bar D + AC$

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