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Find the minimum sum of products form of the below Logic function :

$$F(A,B,C,D) = \sum m(0,2,8,10,15) + \sum d(3,11,12,14)$$

where $m$ and $d$ are min-terms and don’t care conditions respectively.

1. $AC +\bar BC \bar D +B\bar C$
2. $\bar B \bar D + AC$
3. $\bar AC +BC+\bar B\bar C \bar D$
4. $B\bar C\bar D + \bar BA + CA$

00 01 11 10
00 1   X 1
01
11 X   1 X
10 1   X 1

We get 2 prime implicants,

$\bar B \bar D + AC$

by

1
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