0 votes 0 votes Reduce this Boolean Expression to one literal $$\bar W X( \bar Z +\bar YZ ) + X( W+\bar WYZ)$$ $W$ $Z$ $X$ $Y$ Digital Logic digital-logic go-digital-logic-1 boolean-algebra + – Bikram asked Sep 20, 2016 Bikram 407 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Answer : C. We can use the Kornaugh map as the it is the sum of Product of terms (4,5,6,7,12,13,14,15) so it came out to be = X. Arpit Dhuriya answered Oct 28, 2016 Arpit Dhuriya comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes F = w'x(z' + y'z) + x(w + w'yz) = w'x(z' + y')(z' + z) + x(w +w')(w + yz) = w'x(z' + y') + x(w + yz) = x(w'z' + w'y' + w + yz) = x((w +w')(w + z') + w'y' + yz) = x(w + z' + w'y' +yz) = x((w + w')(w + y') + (z' +y)(z' + z)) = x(w + y' + z' + y) = x(w + z' + 1) = x*1 = x skraj answered Jan 27, 2017 skraj comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Answer : C Convert expression into minterms : m(8,9,10,12,13,15) and using k map Final expression is X. k map expression is = XW' + XYZ + XY'Z' = XW' + X = X shaktisingh answered Nov 22, 2019 shaktisingh comment Share Follow See all 0 reply Please log in or register to add a comment.