(1217)_{8 }= (001010001111)_{2}

Making Groups of four digits from the Right Hand side.

(NOTE :- Hexadecimal representation required 4 bits there fore we are taking group of four bits)

(0010 1000 1111)_{2}

Which is (28F)_{16 }

OR (028F)_{16}

Hence answer is B) (028F)_{16}