215 views

2 Answers

2 votes
2 votes

F(p , q , r) = pq + qr' + pr'

pq/r 00 01 11 10
0 0 1 1 1
1 0 0 1 0

Hence : Min-term exp == m2 + m4 + m6 + m7

Answer:

Related questions

0 votes
0 votes
1 answer
1
Bikram asked Sep 20, 2016
196 views
The minimum number of $T$ –gates required to implement the following function is$$F(w,x,y,z) = \sum m (0,1,2,4,7,8,9,10,12,15) $$
0 votes
0 votes
0 answers
2
Bikram asked Sep 20, 2016
131 views
Latches constructed with NOR and NAND gates tend to remain in the latched condition due to which configuration feature?cross couplinggate impedancelow input voltagesasync...
0 votes
0 votes
2 answers
3
Bikram asked Sep 20, 2016
251 views
The minimum number of gates required to implement the Boolean function $(AB+C)$ if we have to use only 2-input NOR gate?
0 votes
0 votes
2 answers
4
Bikram asked Sep 20, 2016
281 views
Zero has only one representation inSign magnitude1's complement2's complementBoth 1's complement and 2's complement