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Determine the Radix $r$

$$(BEE)_r = (2699)_{10}$$

plz explain???
$11r^2 + 14r + 14 = 2699$

$11r^2 + 14r - 2685 = 0 \Rightarrow r = 15$

(BEE)$_{r}$=2699

$11r^{2}+14r+14=2699$

solving it $\frac{-14\pm \sqrt{14^{2}+4*2685*11}}{22}$

r=15
by

### 1 comment

Here, it is assumed A=10, B=11, so on.. which is a property of hexadecimal system.. not any arbitrary system. Hence, from that perspective, this question is badly framed(wrong) in my opinion.

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