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GATE Overflow | Digital Logic | Test 1 | Question: 29
Bikram
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Sep 20, 2016
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The minimum number of gates required to implement the Boolean function $(AB+C)$ if we have to use only 2-input NOR gate?
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Bikram
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3 (A+B)(A+C)
Shivam Chauhan
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Sep 23, 2016
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Shivam Chauhan
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We can write the finle result as
((A'+C')' + (B'+C')')' = F
Which is equal to 3 Nor gate required.
Arpit Dhuriya
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Nov 2, 2016
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Arpit Dhuriya
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