0 votes 0 votes The minimum number of gates required to implement the Boolean function $(AB+C)$ if we have to use only 2-input NOR gate? Digital Logic digital-logic go-digital-logic-1 numerical-answers min-no-gates + – Bikram asked Sep 20, 2016 Bikram 261 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 3 (A+B)(A+C) Shivam Chauhan answered Sep 23, 2016 Shivam Chauhan comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes We can write the finle result as ((A'+C')' + (B'+C')')' = F Which is equal to 3 Nor gate required. Arpit Dhuriya answered Nov 2, 2016 Arpit Dhuriya comment Share Follow See all 0 reply Please log in or register to add a comment.