The answer is (C).
First we show that Q2 $\subseteq$ Q1. Lets consider some examples.
R S T
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1 1 1 2 2 1
1 2 2 1 2 2
2 1 2 2 2 3
Q1: (1,1) (1,2) (1,2) (2,1)
Q2: (1,1) (1,2) (1,2)
Hence, proved.
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Now, we disprove that Q1 $\subseteq$ Q2 is ever possible.
Q1 is subtracting T only once while Q2 is subtracting T twice. So, possiblity of having tuples in Q1 more than Q2 is necessarily more than Q2.
Hence, Q1 $\subseteq$ Q2 is never possible.
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Hence, answer (C).