The Gateway to Computer Science Excellence
First time here? Checkout the FAQ!
x
+11 votes
1k views

Consider the following statements:

  • S1: The sum of two singular $n \times n$ matrices may be non-singular
  • S2: The sum of two $n \times n$ non-singular matrices may be singular


Which one of the following statements is correct?

  1. $S1$ and $S2$ both are true
  2. $S1$ is true, $S2$ is false
  3. $S1$ is false, $S2$ is true
  4. $S1$ and $S2$ both are false
asked in Linear Algebra by Veteran (59.5k points)
edited by | 1k views

6 Answers

+15 votes
Best answer
Yes A is correct option!, Both statements are True

$S_{1}:\text{True}$

$A=\begin{matrix} 2&10 \\ 1&5 \end{matrix}$$\qquad B=\begin{matrix} 3&6 \\ 2&4 \end{matrix}$

 

$|A|=0 \quad |B|=0$

$|A+B|={-3}$

 

$S_{2}:\text{True}$

$A=\begin{matrix} 1&0 \\ 0&1 \end{matrix}$$\qquad B=\begin{matrix} 0&1 \\ 1&0 \end{matrix}$

 

$|A|=1 \quad |B|={-1}$

$|A+B|=0$
answered by Boss (17.1k points)
edited by
+6 votes
ans should be A.

for S1 :  singular matrices matrix[0,0,0,1] + matrix[1,0,0,0] = matrix[1,0,0,1], which is non singular

for S2 : non-singular matrices matrix[1,0,0,1] + matrix[0,1,1,0] = matrix[1,1,1,1], which is singular
answered by Loyal (8.2k points)
0
but matrices should be square ..?
0
yes, that is true
+3 votes
A singular matrix is a square matrix whose determinant is 0. Whenever you solve question related to determinant, think of triangular matrix, like upper triangular matrix, because its determinant is just product of diagonal entries, and so easy to visualize. So definitely, in a singular matrix, one of the entries in diagonal must be zero. Similarly, in non-singular, none of the entries should be zero.

Now take any matrices and just check .

So we see that both S1 and S2 are true. So option (A) is correct.
answered by Active (2k points)
edited by
+2 votes
I think there is a contradiction  Let me explain with example
 If A = [ 2 10
            1  5]
B = [ 3 6
        2  4]
 Sum [ 5 16
           3  9]
| sum| = 9×5_16×3=- 3 which is not equal to zero . So it is non singular
answered by (41 points)
edited by
+1 vote

det (A + B)  is not equal to det (A) + det (B), it means that

if A and B both are singular then, the determinant of sum of A and B may not to be equal to 0.

S1 is correct

Similarly, if A and B are non singular matrix, then det(A+B) may not be Non Zero, it can be Zero means Singular.

S2 is also correct

answered by Junior (773 points)
0 votes

$\boldsymbol{\textbf{A. Is correct option }}$

answered by Active (2.3k points)


Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true

38,235 questions
45,737 answers
133,029 comments
49,928 users