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Consider the following statements:

• S1: The sum of two singular $n \times n$ matrices may be non-singular
• S2: The sum of two $n \times n$ non-singular matrices may be singular

Which one of the following statements is correct?

1. $S1$ and $S2$ both are true
2. $S1$ is true, $S2$ is false
3. $S1$ is false, $S2$ is true
4. $S1$ and $S2$ both are false
edited | 1.4k views
0

I think that without taking any example we can get the answer. Following is the explaination for the two statements.

statement 1 : let us consider any two matrices of n-by-n which are singular, where n >= 2 (beacuse for n = 1 we can only have 1 matrix which is singular). Now, the addition of these two matrices may be singular or nonsingular. Assume that all such possible pairs of matrices yield the sum as non-singular, then certainly statement 1 is true. Now, assume only some possible pairs of n-by-n matrices yield the sum as non-singular while others as singular, then also statement 1 is true, due to the keyword "may be" in the statement. Now, assume the last possibility that all pairs of such matrices yield as singular matrix , then also statement 1 is true again due to "may be" keyword. Hence, statement 1 is true for all cases.

statement 2 : we can argue similarly that statement 2 is also true in all cases.

Hence option A is right answer. Please correct me if I am wrong.

ans should be A.

for S1 :  singular matrices matrix[0,0,0,1] + matrix[1,0,0,0] = matrix[1,0,0,1], which is non singular

for S2 : non-singular matrices matrix[1,0,0,1] + matrix[0,1,1,0] = matrix[1,1,1,1], which is singular
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but matrices should be square ..?
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yes, that is true
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They are square matrices--

$\begin{matrix} 0&0 \\ 0&1\end{matrix}\quad +$ $\quad\begin{matrix} 1&0 \\ 0&0\end{matrix}$

$=\begin{matrix} 1&0\\0&1\end{matrix}$

$\implies (singular+singular)\;$ may be non singular
A singular matrix is a square matrix whose determinant is 0. Whenever you solve question related to determinant, think of triangular matrix, like upper triangular matrix, because its determinant is just product of diagonal entries, and so easy to visualize. So definitely, in a singular matrix, one of the entries in diagonal must be zero. Similarly, in non-singular, none of the entries should be zero.

Now take any matrices and just check .

So we see that both S1 and S2 are true. So option (A) is correct.
edited by
I think there is a contradiction  Let me explain with example
If A = [ 2 10
1  5]
B = [ 3 6
2  4]
Sum [ 5 16
3  9]
| sum| = 9×5_16×3=- 3 which is not equal to zero . So it is non singular
edited
+1 vote

det (A + B)  is not equal to det (A) + det (B), it means that

if A and B both are singular then, the determinant of sum of A and B may not to be equal to 0.

S1 is correct

Similarly, if A and B are non singular matrix, then det(A+B) may not be Non Zero, it can be Zero means Singular.

S2 is also correct

+1 vote

$\boldsymbol{\textbf{A. Is correct option }}$ 0

Yes, you are right.

Using counterexample is a good way to solve such type of problems.