sir... it just as we subtracting intersection from both side of circle and adding individual probablity ??

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Let |M| = students that failed in Maths, and |D| = students that failed in Digital.

$|M| = 875$

$|D| = 1050$

$|M \cap D| = 375$

To find: $| \overline{M}\cup \overline{D}| - | \overline{M} \cap \overline{D}|$

which is equivalent to finding: $| \overline{M \cap D}| - | \overline{M \cup D}|$

which is equivalent to finding: $2500- |M \cap D| - (2500-|M \cup D|)$

We know, $|M \cap D|$ = 375.

Now, $|M \cup D|$ = $875+1050-375=1550$

So, finally we have: $2500- |M \cap D| - (2500-|M \cup D|)$

=> $2500- 375 - (2500-1550)=1175$

$|M| = 875$

$|D| = 1050$

$|M \cap D| = 375$

To find: $| \overline{M}\cup \overline{D}| - | \overline{M} \cap \overline{D}|$

which is equivalent to finding: $| \overline{M \cap D}| - | \overline{M \cup D}|$

which is equivalent to finding: $2500- |M \cap D| - (2500-|M \cup D|)$

We know, $|M \cap D|$ = 375.

Now, $|M \cup D|$ = $875+1050-375=1550$

So, finally we have: $2500- |M \cap D| - (2500-|M \cup D|)$

=> $2500- 375 - (2500-1550)=1175$