online

Question

Comments

Someone please give answer with proper explaination.

---

D.. ?

---

Yes, but how???

Answer 1

Length of binary string (Base 2) = N

In the same system, take the length of ternary string (Base 3) corresponding to the binary string = K

So, for the same system, we have

=> (2)^N - 1 = (3)^K - 1

=> (2)^N  = (3)^K      (Take log on both the sides)

=> N log2 = K log3

=> K = N log2 / log3

=> K = N log₃ 2

So, option D).

Comments

how did you get 2^n-1=3^k-1??

---

refer => http://www.exploringbinary.com/number-of-bits-in-a-decimal-integer/

Answer 2

A n bit string can give 2ⁿ values in binary system

similary it will be 3 powers in ternary...but with n bit strings it can represent more values...so less than n will be needed ...

let that be k bits

3^k=2ⁿ

k = nlog₃2

Comments

you are wrong man

the maximum number denoted by n bit binary string is 2^n-1

pls correct it

---

bro, i am not saying the maximum value, i am saying about number of values..plz read the answer properly

---

My bad

but you have to solve for max Number