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Q : Two computers A and B are to be sold . A salesman who is assigned the job of selling these has the chances of 60 percent and 40 percent respectively to get success.The two computers may be sold independently.Given that at least one computer has been sold , the probability that computer A has been sold is ..........(Round off your answer correct to 2 decimal places).
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Here it is given atleast 1 computer is sold.

Now, we have to find the probability that A is sold

So, here 3 chances

1) A sold

2) B sold

3) both sold

So, among these 3 chances probability of A sold= $\frac{1}{3}\times \frac{40}{100}$

Probability of B sold=$\frac{1}{3}\times \frac{60}{100}$

Probability of both sold=$\frac{1}{3}\times 1$

So,total probability= $\frac{\frac{1}{3}\times \frac{40}{100}+\frac{1}{3}\times 1}{\frac{1}{3}\times \frac{40}{100}+\frac{1}{3}\times \frac{60}{100}+\frac{1}{3}\times 1}$=$\frac{7}{10}$

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