c is exponential so it has higher growth and a is logn which has least growth...b/w b and c
n/logn<= c* nlog2n
because nlog2n , we can write as n * lognlogn
which is obviously larger than n/logn
for ex: let n=2^20
n*lognlogn = 2^20 *20 *20
and n/logn = 2^20/20
hence (A) is the answer