1 votes 1 votes Suppose Ethernet physical addresses are chosen at random ( using true randombits). The probability that on a 1024-host network, two addresses will be the same? A) 1.77 x 10^-9 B) 1.87 x 10^-9 C) 1.99 x 10^-9 D) 1.98 x 10^-8 tvkkk asked Oct 4, 2016 tvkkk 467 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply papesh commented Oct 4, 2016 reply Follow Share is B?? 0 votes 0 votes tvkkk commented Oct 4, 2016 reply Follow Share I also got B. I think it's correct. 0 votes 0 votes Lone Wolf commented Oct 4, 2016 reply Follow Share could you explain??? how it is B? 0 votes 0 votes Please log in or register to add a comment.