I have tried in this way -
No of 4 digit even numbers= Total no of 4 digit even numbers - Number having 0 at the front
Total no of 4 digit even numbers =last place is filled in 2,4,6,8,0 ie 5 ways. Next place in 9 ways, next in 8 ways and next in 7 ways (go from right)
Number having 0 at the front = last place is filled in 2,4,6,8 ie 4 ways, next place in 8 ways and next in 7 ways and first place is for 0.
Required number of numbers = (7*8*9*5)-(7*8*4) = 2520-224 = 2296