Binomial trials
Here we require exactly k success where probability of success is 1/n and of failure is 1-1/n. So
Pr = n_{Ck }(1/n)^k(1-1/n)^(n-k)
So option b is correct
http://math.stackexchange.com/questions/801129/slot-size-bound-for-chaining
Gatecse
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For creating automatas you can also ...