but we can also implement queue using single stack if other constraints also givenhttp://gateoverflow.in/2007/gate2014-2-41

14 votes

What is the minimum number of stacks of size $n$ required to implement a queue of size $n$?

- One
- Two
- Three
- Four

2

1

It may look like only one stack is required but REVERSE operation can't be done without another stack.

Therefore minimum 2 stacks are required.

1

what do you mean by if the reverse is already given??

In this question, queue implemented using the stack.

maintaining the queue property, First-In-First-Out (or) Last-In-Last-Out, we need a minimum of two stacks.

24 votes

Best answer

**A queue can be implemented using two stacks.**

Let queue be represented as " $q$ "

and stacks used to implement $q$ be "stack1" and "stack2".

$q$ can be implemented in two ways:

**Method 1 (By making EnQueue operation costly)**

This method makes sure that newly entered element is always at the bottom of stack 1, so that deQueue operation just pops from stack1. To put the element at top of stack1, stack2 is used.

$enQueue(q, x)$

- While stack1 is not empty, push everything from stack1 to stack2.
- Push $x$ to stack1 (assuming size of stacks is unlimited).
- Push everything back to stack1.

$dnQueue(q)$

- If stack1 is empty then error
- Pop an item from stack1 and return it

**Method 2 (By making deQueue operation costly)**

In this method, in en-queue operation, the new element is entered at the top of stack1. In de-queue operation, if stack2 is empty then all the elements are moved to stack2 and finally top of stack2 is returned.

$enQueue(q, x)$

- Push $x$ to stack1 (assuming size of stacks is unlimited).

$deQueue(q)$

- If both stacks are empty then error.
- If stack2 is empty

While stack1 is not empty, push everything from stack1 to stack2. - Pop the element from stack2 and return it.

Correct Answer: $B$