0 votes 0 votes 1) if |L1| < |L2| then L1 must be finite Trye/False? Theory of Computation finite-automata + – amarkaswan asked Oct 12, 2016 amarkaswan 293 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes i think it is false B/C |L2| can be uncountable and |L1| can be countable Shubham Pandey 2 answered Oct 16, 2016 Shubham Pandey 2 comment Share Follow See all 0 reply Please log in or register to add a comment.