Counters+Frequency

Question

___________ $\text{kHz}$ is the sum of frequencies at the points $a, b,c \text{ and } d$.

 

Answer 1

A Counter also acts as a frequency divider means when a clock of frequency $f$ passes through a mod $n$ counter, then frequency of outcoming clock $= \frac{f}{n}$

• $10$ bit ring counter acts as a $mod-10$ counter. So, frequency at point $a$ is $\color{red}{\frac{100}{10} = 10}$ kHZ
• Frequency  at point $b$ is $\color{red}{\frac{10}{20} = 0.5}$ kHz
• $4 - bit$ parallel counter means a $4-bit$ synchronous counter i.e., $mod-16$ counter. So, frequency at $c = \color{red}{\frac{0.5}{16} = 0.03125}$ kHz
• $4-bit$ Johnson counter is $mod-8$ counter. So, frequency at $d$ is  $\color{red}{\frac{0.03125}{8} = 0.00390625}$

Sum of frequencies at these points $\color{navy}{= 10 + 0.5 + 0.03125 + 0.003906 = 10.535156}$ kHz

Comments

thanks @mcjoshi.

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Do you have any refrence for the same ?

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N bit Ring counter are mod n counter

N bit johnson counter are mod 2n counter

N bit synchronous or asynchronous counter are mod2^N counter