@habibkhan.@prabhanjan_1
What I found was like this way..
insert 3,10,12,14.....and split on 10.So 10 goes up and 3 on Left child(min 1 key on a node) and 10,12,14 right child(max key on a node).So I am keeping Right child always full so that i get max no of spilts all the time.(Becoz inputs are in ascending order).
So from 14 onwards for all key input it is a split on leaf node.
Hence total no of split=7.(correct me if i m wrong)