1 votes 1 votes KISHALAY DAS asked Oct 21, 2016 KISHALAY DAS 494 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes line 1 is always 0. o/p of and gate is always 0. inputs to last level NOR gate become 0 and (C+D)' 0 NOR (C+D)= (0+(C+D)')' = 1(C+D)= C+D Anusha Motamarri answered Oct 21, 2016 Anusha Motamarri comment Share Follow See all 2 Comments See all 2 2 Comments reply KISHALAY DAS commented Oct 21, 2016 reply Follow Share Yes thats true.But see If o/p of NAND gate is 0 that means both the input are 1 i.e C=1,D=1. So It would me C+D=1 too.is not that true? 1 votes 1 votes Prateek kumar commented Jan 3, 2018 reply Follow Share yeah i agree with @Kishalay Das it will be "1" 0 votes 0 votes Please log in or register to add a comment.