Made Easy Test Series Computer Network Question

Question

Consider a network connecting two systems located 4000 kilometers apart. The
bandwidth of the network is 64 Mbps. The propagation speed of the media is 2/3 of
the speed of light in vacuum. It is needed to design selective repeat sliding
window protocol for this network. The average packet size is of 8 Kb. The network
is to be used to its full capacity. Assume that processing delays at nodes are
negligible. Then, the minimum size in bits of the sequence number field has to be..........?

Comments

is it 12?

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10 bits should be answer because it is SR protocol.

Answer 1

The network is to be used to its full capacity

that means Efficiency is 100%

$\eta =N\div 1+2\alpha$

$\eta=1

N=1+2\alpha$     \alpha$ =T_p/T_t

T_p/T_t =160

N= 1+2*160  = 321

N= window Size

Minimum size in bits of the sequence number field =log₂(321)= 9 bits after Ceil

Comments

but the in selective repeat protocol the sequence no. is 2N