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4 votes
4 votes

Suppose there are 4 nodes N1, N2, N3 and N4 are using a slotted ALOHA channel to send their own huge data. When competing all the nodes to transfer their data only one node will get succeeded with a probability P. The time is divided into slots S1, S2, S3 ….and so on. What is probability of N1 succeeded in slot 5?

  1. 4*(1-P)3(P(1-P)3)
  2.   P(1-P)3(1-P(1-P)3)
  3.   4*P(1-P)3(1-P(1-P)3)
  4. 4*P(1-P)3(1-P3(1-P)3)

1 Answer

5 votes
5 votes

To win the race probability at each slot= P*(1-P)

and to loss the race probability at each slot= 1- P*(1-P)  

so till 4 slots it lost = 4 (1- P*(1-P))

and at the fitth slot won the race=P*(1-P)

So ans should be  4* (1- P*(1-P))  P*(1-P)=  4*P(1-P)3(1-P(1-P)3)

correct me!

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