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If $\large\left(z + \dfrac{1}{z}\right)^{2}= 98$, compute $\large \left(z^{2} +\dfrac{1}{z^{2}}\right)$.
asked in Numerical Ability by Boss (18.3k points)
edited by | 794 views

2 Answers

+17 votes
Best answer
$\quad \left(Z+\dfrac{1}{Z}\right)^{2}$

$= \left(z^{2} + 2(z)\left(\dfrac{1}{z}\right) + \left(\dfrac{1}{z}\right)^{2}\right) = \left(z^{2} + \dfrac{1}{z^{2}}\right)+2 =98$

$\Rightarrow 98-2 = 96$ is answer..
answered by Active (1.1k points)
edited by
+1 vote
answer is 96
answered by Loyal (8.6k points)
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