The Gateway to Computer Science Excellence
First time here? Checkout the FAQ!
x
+7 votes
618 views
If $\large\left(z + \dfrac{1}{z}\right)^{2}= 98$, compute $\large \left(z^{2} +\dfrac{1}{z^{2}}\right)$.
asked in Numerical Ability by Veteran (14.6k points)
edited by | 618 views

2 Answers

+13 votes
Best answer
$\quad \left(Z+\dfrac{1}{Z}\right)^{2}$

$= \left(z^{2} + 2(z)\left(\dfrac{1}{z}\right) + \left(\dfrac{1}{z}\right)^{2}\right) = \left(z^{2} + \dfrac{1}{z^{2}}\right)+2 =98$

$\Rightarrow 98-2 = 96$ is answer..
answered by Active (1.2k points)
edited by
+1 vote
answer is 96
answered by Boss (7.7k points)


Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true

32,470 questions
39,199 answers
109,000 comments
36,575 users