ceil(1250/3)=417 blocks are required
so for each block one 417 pointers are required so number of blocks is ceil(417/11)=38 ---------1st level
again these 38 blocks are to be indexed so 38 pointers so number of blocks is ceil(38/11)=4-----2nd level
again 4 pointers so ceil(4/11)=1-----3rd level
min index blocks=38+4+1=43
min levels are 3